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New Velocity/Distance Question 1/25

  1. Jan 25, 2015 #1

    ilh

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    1. The problem statement, all variables and given/known data
    In reaching her destination, a backpacker walks with an average velocity of 1.44 m/s, due west. This average velocity results, because she hikes for 5.48 km with an average velocity of 3.25 m/s due west, turns around, and hikes with an average velocity of 0.683 m/s due east. How far east did she walk (in kilometers)?


    2. Relevant equations

    v1 = 3.25 m/s west
    d1= 5480 m
    t1= 1686

    v2 = 0.638 m/s east
    d2 = ?
    t2= ?
    3. The attempt at a solution

    I know I have to plug in my numbers into the formula but I do not know how to derive second time or distance. Please help.

     
  2. jcsd
  3. Jan 25, 2015 #2

    PhanthomJay

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    What is the formula for average velocity?
     
  4. Jan 25, 2015 #3

    ilh

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    V = D/T
     
  5. Jan 25, 2015 #4

    haruspex

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    You successfully found t1 by an equation. You have two more such equations available: one for the return trip and one for the trip as a whole. You have two unknowns.
     
  6. Jan 25, 2015 #5

    PhanthomJay

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    But what does D represent when finding average velocity?and T?
     
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