Newtonian Central Force System

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SUMMARY

The discussion centers on the integration of the equation X/|X|^3 = grad U(X), leading to the potential energy function U(X) = -1/|X|. The user expresses difficulty in integrating this correctly and questions the form of grad U(X) when U(X) is modified to U(X) = -1/(|X|^v). The correct expression for the gradient of U(r) is confirmed as ∇U(r) = 1/r^2 in the radial vector context, indicating a clear relationship between the potential energy and the radial distance.

PREREQUISITES
  • Understanding of vector calculus, specifically gradient operations.
  • Familiarity with potential energy functions in physics.
  • Knowledge of radial vectors and their properties.
  • Basic integration techniques in calculus.
NEXT STEPS
  • Study the derivation of potential energy functions in central force systems.
  • Learn about the implications of varying constants in potential energy equations, such as U(X) = -1/(|X|^v).
  • Explore vector calculus applications in physics, focusing on gradient and divergence.
  • Investigate the physical significance of radial vectors in gravitational and electrostatic fields.
USEFUL FOR

Students and professionals in physics, particularly those studying classical mechanics and central force systems, as well as mathematicians focusing on vector calculus applications.

itev07
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I have a problem and can’t seem to work it out! Ok, here goes:

X/|X|^3 = grad U(X)

which, when integrated gives

U(X)= -1/|X|

But I can’t seem to integrate to get the correct answer. Also, if

U(X)= -1/(|X|^v )

where v is a constant, then what is grad U(X) now? Thanks for reading and any help will be much appreciated!
 
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itev07 said:
I have a problem and can’t seem to work it out! Ok, here goes:

X/|X|^3 = grad U(X)

which, when integrated gives

U(X)= -1/|X|

Probably X on the LHS is a radial vector [tex]\vec{r}[/tex].

[tex]\frac{\vec{r}}{r^3}=\nabla U(r)[/tex]

[tex]\nabla U(r)=\frac{\hat{r}}{r^2}[/tex]

Integrate, U(r)=-1/r.
 

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