Newton's Theory of Gravity: Calculating the Orbit of Our Solar System

  • Thread starter Thread starter mcnealymt
  • Start date Start date
  • Tags Tags
    Gravity Theory
Click For Summary
The discussion revolves around calculating the solar system's orbital period, the number of orbits completed, and estimating the mass of the galactic center. For part A, the orbital period can be determined using the formula T = (2πr)/v, where the radius is derived from the distance in light years converted to meters. Part B involves using the calculated period to find how many orbits the solar system has completed since its formation 5 billion years ago. Parts C and D require applying gravitational force equations to estimate the mass of the galactic center and the number of stars within it, emphasizing the relationship between centripetal force and gravitational force. The conversation highlights the need for proper unit conversions and understanding of gravitational dynamics in orbital mechanics.
mcnealymt
Messages
35
Reaction score
0

Homework Statement


The solar system is 25,000 light years from the center of our Milky Way galaxy. One light year is the distance light travels in one year at a speed of 3.0*10^8 m/s. Astronomers have determined that the solar system is orbiting the center of the galaxy at a speed of 230 km/s.

A)Assuming the orbit is circular, what is the period of the solar system's orbit? Give your answer in years.

B) Our solar system was formed roughly 5 billion years ago. How many orbits has it completed?

c) The gravitational force on the solar system is the net force due to all the matter inside our orbit. Most of that matter is concentrated near the center of the galaxy. Assume that the matter has a spherical distribution, like a giant star. What is the approximate mass of the galactic center?

D)Assume that the sun is a typical star with a typical mass. If galactic matter is made up of stars, approximately how many stars are in the center of the galaxy?

Homework Equations





The Attempt at a Solution



A) I know the period by using the equation
v=(2pi * r)/ T
T= (2pi *r)/ v
My problem I can't even interpret the given information. I know that 25,000 light years has something to do with the radius. I have a feeling that I'm supposed to multiply 25,000 light years with 3.0 *10^8



For parts B-D I am completely lost...
 
Physics news on Phys.org
mcnealymt said:
My problem I can't even interpret the given information. I know that 25,000 light years has something to do with the radius. I have a feeling that I'm supposed to multiply 25,000 light years with 3.0 *10^8

Almost.

Distance(m) = Velocity(m/s) * time(s)

Time = 25,000 years
Velocity = 3.0*10^8 m/s

You need to convert 25,000 years to seconds first
 
More hints..

For A..

If you know the radius you can calculate the circumference of the orbit.
The velocity is stated so you can work out how long it takes to make one orbit.

For B..

If you know how long one orbit takes (from B) and you know how old the earth/solar system is you can work out how many orbits the solar system might have made in it's lifetime to date.

For C and D...

Centripetal force is provided by gravity. Whats the equation for the force of gravity between two bodies?
 
Okay for part A) I found the radius and can use the equation T= (2pi*r)/v .

B) How does the age of the solar system help me? It just states an age and nothing else.

C) & D) The equation is g= (G*m1*m2)/r^2

However, what would be the mass of the galactic center in this equation?
 
mcnealymt said:
B) How does the age of the solar system help me? It just states an age and nothing else.
For example, you know that the Earth's orbital speed is one orbit per year. How many orbits has it completed since it was formed 4,5 billion years ago?

Same here, only the speed is different.

C) & D) The equation is g= (G*m1*m2)/r^2

However, what would be the mass of the galactic center in this equation?
This is the equation for gravitational force, so you should label it Fg. g is the acceleration in a gravitational field.
In there, one mass is the mass of the orbiting body, the other one is that of the central body.

For circular motion, the force tugging on the orbiting body(the above) needs to be exactly equal to the value known as centripetal force.
Can you take it from here? Write the equation and see if you can get rid of any variables.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
10
Views
3K