NMR Spectrum - expected triplets appear as singlets

  • Thread starter Thread starter chemistryfourm
  • Start date Start date
AI Thread Summary
The discussion centers on the unexpected NMR results for diethyl cyclopent-3-ene-1,1-dicarboxylate, where proton environments that should appear as doublets are observed as singlets. This anomaly has been consistently noted by multiple lab members, prompting an exploration of potential explanations. Four main possibilities are identified: the samples may not be as presumed, the NMR resolution might be inadequate, the NMR equipment could require maintenance, or there may be a misunderstanding of expected results. Further insights suggest that molecular resonance and the orientation of hydrogens in the ring could influence the observed spectra. Specifically, the Karplus equation is mentioned, indicating that certain hydrogen orientations can lead to low coupling constants, affecting the multiplicity. Additionally, the symmetry of the molecule is raised as a factor that might impact the spectrum, with references to external resources confirming similar spectral observations for the compound in question.
chemistryfourm
Messages
1
Reaction score
0
TL;DR Summary
My NMR of diethyl cyclopent-3-ene, 1, 1 , dicarboxylate shows the cyclic proton environments both as singlets where they are expected to be a doublet and triplet
My NMR of diethyl cyclopent-3-ene, 1, 1 , dicarboxylate shows the cyclic proton environments both as singlets where they are expected to be a doublet and triplet.
Proton env B would be epxected to be a doublet and D to be a doublet. Everyone in the lab got the same result. Is there an explanation as to why it they are singlets and not multiplets as expected? The chemical shift and integration suggest they are the expected proton enviornment however the multiplicity is not as expected.
NMR exp 2.png
nmr exp 2.png
 
Chemistry news on Phys.org
It seems there are only 4 general possibilities:
1) the specimens are not what you think they are
2) plot resolution is not sufficient to resolve close peaks
3) NMR machine needs servicing
4) you have an incorrect expectation of results

Cheers,
Tom

p.s. Please let us know what you find causing the effect.
(we all like to learn!)
 
Tom.G said:
It seems there are only 4 general possibilities:

There is more, for example in some molecules resonance can change the "average" observed structure, making the spectra different from the one that looks obvious and logical. I doubt that's the case here though.
 
I think it is the orientation of the hydrogens in the ring. Check the Karplus equation. You will see that certain orientations lead to low values for J(H-C-C-H). The protons at the double bond - D - are in the plane of the ring, the ones at position B are on tetrahedral carbons and not in the same plane.

So then I googled the proton spectrum of your product, and got the same spectrum as you have.
See this https://www.rsc.org/suppdata/cc/b6/b618341g/b618341g.pdf and look at the first spectrum.

I actually googled proton nmr of cyclopent-3-ene first and up came your product.
 
What effect does the symmetry of the molecule have on the observed spectrum?
 
I want to test a humidity sensor with one or more saturated salt solutions. The table salt that I have on hand contains one of two anticaking agents, calcium silicate or sodium aluminosilicate. Will the presence of either of these additives (or iodine for that matter) significantly affect the equilibrium humidity? I searched and all the how-to-do-it guides did not address this question. One research paper I found reported that at 1.5% w/w calcium silicate increased the deliquescent point by...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
I'm trying to find a cheap DIY method to etch holes of various shapes through 0.3mm Aluminium sheet using 5-10% Sodium Hydroxide. The idea is to apply a resist to the Aluminium then selectively ablate it off using a diode laser cutter and then dissolve away the Aluminium using Sodium Hydroxide. By cheap I mean resists costing say £20 in small quantities. The Internet has suggested various resists to try including... Enamel paint (only survived seconds in the NaOH!) Acrylic paint (only...
Back
Top