No. of trials for P>0.99 of at least one basket ball success

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SUMMARY

The discussion centers on calculating the number of trials required to achieve a probability of at least one success in a basketball shooting scenario, where the probability of success in a single trial is 0.75 (P(p) = 0.75). The derived formula for the probability of no successes in n trials is P_n( \bar p) = (0.25)^n. To ensure at least one success with a probability of 0.99, the inequality 1 - (0.25)^n ≥ 0.99 leads to n ≥ 4. Therefore, a minimum of 4 trials is necessary to meet the specified probability threshold.

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Homework Statement


upload_2017-11-21_18-36-58.png


Homework Equations

The Attempt at a Solution


Probability of getting no success in one trial ##P( \bar p) = 1 – P (p) = 0.25 ##

Probability of getting no success in n trials ##P_n( \bar p) = (1 – P (p) )^n= (0.25)^n ##

Probability of getting one success in n trials ##P_n( 1p) = 1-(1 – P (p) )^n=1- (0.25)^n ##

We have,

## 1- (0.25)^n \geq 0.99

\\ n \geq 3.3 ##

So, necessary n = 4
Is this correct?
 

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