What is the approach for solving a non-inertial pendulum problem?

  • Thread starter Thread starter inner08
  • Start date Start date
  • Tags Tags
    Inertial Pendulum
Click For Summary

Homework Help Overview

The problem involves a pendulum suspended in a non-inertial frame of reference, specifically on a truck that is accelerating. The pendulum has a length of 80 cm and a mass of 0.4 g, and the discussion centers around determining the horizontal deviation of the mass and the tension in the cord.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to identify the correct formulas and approach for analyzing the forces acting on the pendulum in the context of non-inertial motion. Some participants suggest drawing a free body diagram (FBD) and identifying the forces involved, while others question the setup of the equations related to the angle of deviation.

Discussion Status

The discussion is ongoing, with participants providing insights into the forces acting on the pendulum and clarifying the relationships between them. There is an emphasis on ensuring the correct application of trigonometric functions in relation to the angle of deviation.

Contextual Notes

The original poster expresses uncertainty about the formulas to use and the steps to take, indicating a need for foundational understanding of the problem setup in a non-inertial frame.

inner08
Messages
48
Reaction score
0
Hi,

I have this practice problem I'm trying to figure out.

A pendulum 80 cm in length has a mass of 0.4g is suspended on the roof of a truck accelerating at 2.6m/s/s. Find a) the horizontal deviation of the mass; b) the tension in the cord.

For a, I know the answer is 20.6cm but I really have no clue as to where to start, what formulas to use. I've been trying for a couple of hours with the formulas I have and can't seem to get the correct answer. I do know this would be a non-inertial frame of reference type of problem but I'm stuck as to how I arrive to that answer.

For b, I thought i'd use the pythagorean equation since we have the weight and the force F' making a 90 degree angle. So I did sqrt((mg)^2 + (ma)^2) = 4.06N.

Any insight on how I should approach the first problem and the steps I should take to solve it would be greatly appreciated!

Thanks,
 
Physics news on Phys.org
For (a) start by drawing a FBD of the mass. Note that the mass will be accelerating at the same rate as the truck.
 
Ok. So there are 3 forces (mg, ma and T) acting on the object.

Fx = Tcos(theta) - F'
Fy = Tsin(theta) - mg

Is that right? If so, where do I go from here?
 
Carefull, if you are saying that theta is the angle with the vertical, then you mixed up the sine and cosine.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
17
Views
1K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 27 ·
Replies
27
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
4
Views
1K
Replies
41
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
2K
Replies
7
Views
2K