I can't type in latex so in this post d^2a is the secpnd derivative of a, while (da)^2 is the square of the derivative.(adsbygoogle = window.adsbygoogle || []).push({});

This equation arose from the G_thetatheta compinent of the einstein tensor. Iwas solving tfor the shcwarzchildmetric where where the cosmos constant is nonzero.

the equation is:

e^2a(d^2a +2(da)^2 +2/r(da))= L where L is the cosmological constantand r is the radial coordinate. Umm how do we solve this?

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# Non linear differential equation

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