Non-Uniform Circular Motion - Finding total acceleration

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  • #1
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Homework Statement



21jdoqu.jpg


Homework Equations


Code:
a(total) = sqrt( a(tangential)^2 + a(radial)^2 )

The Attempt at a Solution



I wrote out equations for the forces in the radial and tangential directions:
Code:
F(radial)       = T - ( mg * cos(θ) )
F(tangential) = mg * sin(θ)
I used the equations to find acceleration in the radial and tangential direction (a = F/m):
Code:
a(radial)       = (T/m) - ( g * cos(θ) )
a(tangential) = g * sin(θ)
I plugged it into a(total) = sqrt( a(tangential)^2 + a(radial)^2 ):
JkNfO.gif


which simplifies to:

4oCLY.gif


My answer is incorrect and I'm not sure what I did wrong.
Any help would be appreciated.
 

Answers and Replies

  • #2
911
18
is this some kind of online question bank where you have to submit the answer ?
i see that your solution seems to be correct... may be you need to further simplify the expression you got....these online physics problem banks can act stupid....

newton
 
  • #3
49
0
Your answer seems to be correct. I think you need to simplify the expression by using sin^2(x)+cos^2(x)=1. That may change the final expression, but otherwise, the answer is same.
 

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