Nonlinear second order differential equation

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SUMMARY

The discussion focuses on solving the nonlinear second order differential equation given by \(\frac{\partial^{2}y}{\partial x^{2}} - ay^{-1}\frac{dy}{dx} = 0\), where \(a\) is a constant. The solution involves using the identity \(\frac{\mathrm{d}^2y}{\mathrm{d} x^2} = y'\frac{\mathrm{d}y'}{\mathrm{d}y}\) to express \(y'\) as a function of \(y\). Subsequently, the method of separation of variables is applied to derive the solution. This approach is essential for understanding the behavior of nonlinear differential equations in mathematical physics.

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JulieK
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What is the solution of the follwoing differential equation

[itex]\frac{\partial^{2}y}{\partial x^{2}}-ay^{-1}\frac{dy}{dx}=0[/itex]

where [itex]a[/itex] is a constant.
 
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JulieK said:
What is the solution of the follwoing differential equation

[itex]\frac{\partial^{2}y}{\partial x^{2}}-ay^{-1}\frac{dy}{dx}=0[/itex]

where [itex]a[/itex] is a constant.

Use the identity
[tex]\frac{\mathrm{d}^2y}{\mathrm{d} x^2} = \frac{\mathrm{d}y'}{\mathrm{d}x} =<br /> \frac{\mathrm{d}y'}{\mathrm{d}y}\frac{\mathrm{d}y}{\mathrm{d}x} = y'\frac{\mathrm{d}y'}{\mathrm{d}y}[/tex]
to find [itex]y' = \frac{\mathrm{d}y}{\mathrm{d}x}[/itex] as a function of [itex]y[/itex]. Then use separation of variables.
 
Thank you
 

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