Normal Distribution: Mean & Std Dev for Conditional Expected Values

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Einstein
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A normal distribution can be completely defined by two parameters - the mean and the standard deviation. Given a normal distribution however, say X, how can I use just the mean and the standard deviation to give me conditional expected values for X<=0 and for X>0? I am guessing the distribution can be standardised to obtain a z-statistic.
 
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"Given a normal distribution however, say X" - I assume you mean that the variable [tex]X[/tex] has a normal distribution. Are both [tex]\mu[/tex] and [tex]\sigma[/tex] known?

"how can I use just the mean and the standard deviation to give me conditional expected values for [tex]X \le 0[/tex] and for [tex]X>0[/tex] ?"
This doesn't make sense to me as it stands. In statistics we take expected values of some function of a random variable - can you elaborate on what it is you seek?
 
If X has normal distribution with mean [itex]\mu[/itex] and standard deviation [itex]\sigma[/itex] then [itex]z= (x- \mu)/\sigma[/itex] has the standard normal distribution. As statdad said, "conditional expected values for X< 0 and X> 0" makes no sense." I might interpret as "suppose X a standard normal distribution, restricted to be larger than 0. What is the the expected value of X?"

That would be
[tex]\frac{1}{\sqrt{\pi}}\int_0^\infty x e^{-x^2}dx= \frac{1}{2\sqrt{\pi}}[/tex]
The general problem, with non-zero mean or standard deviation not 1 would be a much harder integral.
 
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