Normalization of time independent wave function

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To normalize the wave function Ψ(x) = A cos(πx/a), the integral of the square of the wave function must equal one, expressed as ∫Ψ*Ψ dx = 1. The user attempts to integrate A² cos²(πx/a) but is unsure about the limits of integration necessary for proper normalization. The discussion emphasizes that normalization requires definite integration over the range where the wave function is defined. Clarifying the limits of integration is crucial for finding the correct normalization constant A, which is ultimately determined to be A = √(2/a).
Skullmonkee
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Homework Statement


normalize the wave function \Psi(x)= Acos(\Pi*x/a) to show that A=\sqrt{2/a}

The Attempt at a Solution


i don't know how to get that answer as all i can tell, normalizing gives:
-A^{2}pi^{2}2x/a^{2} * sin (pix/a)

However this does not give the right answer for A
Any help pointing out what I've missed would be great.
 
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Hi Skullmonkee,

Let me ask you a question first:

What expression "defines" the normalization of a wavefunction?
 
Do you mean this?

\int\Psi^{*}\Psi dx=1

\int Acos(\pi x/a)*Acos(\pi x/a)dx

= \int A^{2}cos^{2}(\pi x/a)

But I am not sure where to go from here?
 
What are the limits of integration? I.e., over what range of x is the wavefunction defined?
 
You need to plug in the limits of integration. You can't normalize a wave function using indefinite integration.
 

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