αιM2=(-1/2+N⊥) then, if N⊥=1/2 αιM2=0, additionally if N⊥=0 then αιM2=-1/2 and so on. When N⊥=1/2 then the fermions are all masless (as M^2 must be equivalent to 0 as α is not) and there are 8 states. I don't know if this is to specific or not described well but my question is: how does one get to the 8 fermion states and how many states would one have when the N⊥ is ,say, equivalent to 3/2? Please excuse, I Couldnt find a better header. Thanks for any help.