- #1
moriheru
- 273
- 17
αιM2=(-1/2+N⊥)
then, if N⊥=1/2 αιM2=0, additionally if N⊥=0 then αιM2=-1/2 and so on.
When N⊥=1/2 then the fermions are all masless (as M^2 must be equivalent to 0 as α is not) and there are 8 states.
I don't know if this is to specific or not described well but my question is: how does one get to the 8 fermion states and how many states would one have when the N⊥ is ,say, equivalent to 3/2?
Please excuse, I Couldnt find a better header. Thanks for any help.
then, if N⊥=1/2 αιM2=0, additionally if N⊥=0 then αιM2=-1/2 and so on.
When N⊥=1/2 then the fermions are all masless (as M^2 must be equivalent to 0 as α is not) and there are 8 states.
I don't know if this is to specific or not described well but my question is: how does one get to the 8 fermion states and how many states would one have when the N⊥ is ,say, equivalent to 3/2?
Please excuse, I Couldnt find a better header. Thanks for any help.