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- Homework Statement:
- Determine the relative amount of low-coordinated atoms (atoms at surfaces, edges, corners) in a cuboid of n atoms edge length. Assume a simple cubic crystal structure.

- Relevant Equations:
- Crystal Structure

Do I do it right guys?

The relative amount of low-coordinated atoms is

The number of atoms at 8 corners: n_corner=8 1/8=1.

The number of atoms at 12 edges: n_edge=12 (n-2)/4=3n-6.

The number of atoms at 6 surfaces: n_surface=6 (n^2-4n)/2=3n^2-12n.

The relative amount of low-coordinated atoms is

n_total=n_corner+n_edge+n_surface=3n^2-9n-5.

The relative amount of low-coordinated atoms is

The number of atoms at 8 corners: n_corner=8 1/8=1.

The number of atoms at 12 edges: n_edge=12 (n-2)/4=3n-6.

The number of atoms at 6 surfaces: n_surface=6 (n^2-4n)/2=3n^2-12n.

The relative amount of low-coordinated atoms is

n_total=n_corner+n_edge+n_surface=3n^2-9n-5.