MHB Number of Integers Between √19 and √90

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The discussion calculates the number of integers between √19 and √90, establishing that √19 is approximately 4.36 and √90 is about 9.49. By subtracting these two values, the difference is found to be 5.1279. Applying the floor function to this result yields the greatest integer less than or equal to 5.1279, which is 5. Therefore, there are 5 integers between √19 and √90.
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How many integers are there between √19 and √90
 
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$4\lt\sqrt{19}\lt5$ and $9\lt\sqrt{90}\lt10$
 
Subtract the lower number from the higher number.

√90 - √19 = 5.1279

Then use the "floor" function on 5.1279. If you are unfamiliar, floor(x) = the greatest integer <= x. (Basically round down)

So the number of integers between these two values is floor(5.1279)=5.
 

Thread 'Area of Overlapping Squares'

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