MHB Number of Integers Between √19 and √90

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The discussion calculates the number of integers between √19 and √90, establishing that √19 is approximately 4.36 and √90 is about 9.49. By subtracting these two values, the difference is found to be 5.1279. Applying the floor function to this result yields the greatest integer less than or equal to 5.1279, which is 5. Therefore, there are 5 integers between √19 and √90.
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How many integers are there between √19 and √90
 
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$4\lt\sqrt{19}\lt5$ and $9\lt\sqrt{90}\lt10$
 
Subtract the lower number from the higher number.

√90 - √19 = 5.1279

Then use the "floor" function on 5.1279. If you are unfamiliar, floor(x) = the greatest integer <= x. (Basically round down)

So the number of integers between these two values is floor(5.1279)=5.
 
Thread 'Erroneously finding discrepancy in transpose rule'

Thread 'Erroneously finding discrepancy in transpose rule'

Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...
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