Number of points having integral coordinates

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utkarshakash
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Homework Statement


Let A,B,C be three sets of complex numbers as defined below

A = {z:|z+1|[itex]\leq[/itex]2+Re(z)}, B = {z:|z-1|[itex]\geq[/itex]1} and
C=[itex]\left\{z: \frac{|z-1|}{|z+1|}\geq 1 \right\}[/itex]

The number of point(s) having integral coordinates in the region [itex]A \cap B \cap C[/itex] is

Homework Equations



The Attempt at a Solution


I worked out and found that [itex]A \cap B \cap C[/itex] is the area bounded by the parabola [itex]y^{2}=2(x+\frac{3}{2})[/itex] and the Y-axis. So the points having integral coordinates in this region are (-1,0), (0,0), (-1,1) and (-1,-1) which counts up to 4. But the correct answer is 6.
 
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Get out a piece of graph paper and carefully graph your region. Note that boundary points are included in the given regions.
 
jambaugh said:
Get out a piece of graph paper and carefully graph your region. Note that boundary points are included in the given regions.

Ughhh... How can I miss (0,-1) and (0,1)! Thanks.