{Number theory} Integer solutions

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Homework Help Overview

The problem involves finding the integer solutions to the equation \(x_1 + x_2 + \cdots + x_{251} = 708\) in positive integers, and determining the value of \(n\) for another equation \(y_1 + y_2 + \cdots + y_n = 708\) that has the same number of solutions, where \(n \neq 251\).

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Some participants discuss the application of the stars and bars theorem, questioning the interpretation of the number of solutions and the implications of the notation used in the problem statement.

Discussion Status

The discussion is ongoing, with participants exploring the meaning of the notation and the implications of the stars and bars method. There are differing interpretations regarding the number of solutions and the conditions under which they apply.

Contextual Notes

There is some confusion regarding the notation used in the problem, particularly about what constitutes the number of solutions and whether permutations of the variables are considered. Participants also raise concerns about the validity of certain solutions based on the constraints of positive integers.

youngstudent16
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Homework Statement


##x_1+x_2 \cdots x_{251}=708## has a certain # of solutions in positive integers ##x_1 \cdots x_{251}##
Now the equation ##y_1+y_2 \cdots y_{n}=708## also has the same number of positive integer solutions ##y_1, \cdots y_n## Where ##n \neq251## What is ##n##

Homework Equations


I think this is a stars and bars problem but I'm not super familiar with it still

The Attempt at a Solution


So looking at the stars and bars page it seems that ##{m \choose k}={m \choose m-k}## so then would ##n## in this case just be ##457##? In this case ##m=707## and ##k=250##

Edit figured it out it is ##458## I just forgot to add 1 back to the original ##n##
 
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I don't think I understand the notation here. You say this problem "has a certain # of solutions in positive integers x 1 ⋯x251" I would take that to mean that it has 251 solutions. You then say "y1+y2 \cdots yn=708 also has the same number of positive integer solutions y1 ,⋯yn y_1, \cdots y_n Where n≠251".

If the first equation has 251 solutions and the next has "the same number" how is it not 251?

And I have no idea what a "stars and bars problem" and a "stars and bars page" are!
 
HallsofIvy said:
And I have no idea what a "stars and bars problem" and a "stars and bars page" are!
I believe it refers to the problem of how many ways of placing r identical objects into n distinct buckets. Maybe the 'bars' represent the divisions between the buckets.
The posted solution, after correction, looks right.
 
HallsofIvy said:
I don't think I understand the notation here. You say this problem "has a certain # of solutions in positive integers x 1 ⋯x251" I would take that to mean that it has 251 solutions.
No, the OP simply means that it "has j solutions", where j is unknown.

HallsofIvy said:
And I have no idea what a "stars and bars problem" and a "stars and bars page" are!
This refers to an interesting class of problems with an elegant path to solution; there are pages that explain this further on both Mathworld and Wikipedia which can be found using a well-known search engine.

Is the question asking for the number of unique solutions, or are permutations of ## x_i ## permitted?
 
... and have you dealt properly with solutions ending with a bar (that will not sum to 708) and solutions starting with one or more stars that will not satisfy that ## x_i ## are positive?

Well done for spotting the stars and bars analogue though, it is not immediately obvious.
 

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