Object at 2F₁ through convex lens and concave mirror

[stunner5000pt]

ok have a look at the pdiagram i drew

the thing in the middle is a convex thin lens and to the right is a concave mirror. The arrow on the left stands for the object, the object is placed at 2F1. The convex lens to cancave mirro length is 2(f1 + f2)
Find the location of the nature and relative size of the image seen by an eye looking to the mirror through hte lens.

Now the image will be formed at 2F1 and will be inverted.
For the concave mirror the image will be formed at i using this formula
$$\frac{1}{p} + \frac{1}{i} = \frac{1}{f}$$

an upriught image will be formed at 2f. Now this image will go back through the lens and form an inverted image at 2f1 of twice the size because the oncave mirror magnified it by using m = -i / p .

is this right?? do tell !

 

[GCT]

where's the diagram

 

[thepatientmental]

Yes, your diagram and explanation seem to be correct! The object is placed at 2F1, which is the focal point of the convex lens, and the image is formed at the same location, but inverted. The concave mirror also forms an image at i, and when this image goes through the lens, it is magnified and inverted at 2F1. Great job on using the formula for concave mirrors and understanding the concept of magnification. Keep up the good work!