Obtaining the decuplet of baryon states from one state

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Discussion Overview

The discussion revolves around the process of obtaining the baryon decuplet states from a single state using ladder operators, specifically focusing on the state ##\Delta^{++}=uuu## and the resulting states derived from it.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant describes applying the ladder operator ##T_-## to the state ##uuu## and obtaining the normalized state ##\frac{1}{\sqrt{3}}(duu+udu+uud)##, questioning why this differs from the expected state ##\Delta^+=uud##.
  • Another participant requests a reference for the material being discussed.
  • A reference is provided to Thomson's book "Modern Particle Physics," indicating specific pages that discuss the application of ladder operators to baryon states.
  • One participant suggests that the notation ##uud## may be used as an abbreviation, implying a potential simplification in the representation of baryon states.

Areas of Agreement / Disagreement

Participants express differing views on the representation of baryon states and the application of ladder operators, indicating that the discussion remains unresolved regarding the normalization and notation of the states.

Contextual Notes

There may be limitations related to the definitions of the states and the normalization process, as well as the assumptions underlying the use of ladder operators that are not fully explored in the discussion.

Xico Sim
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Hi, guys.

If you are given one state of the baryon decuplet (the upper-right state ##\Deltaˆ{++}=uuu##, for instance), you can use the ladder operators to get the other states of the decuplet.
When I apply ##T_-## to uuu and normalizing, I get ##\frac{1}{\sqrt{3}}(duu+udu+uud)##. However, in the decuplet I see ##\Deltaˆ+=uud## instead of ##\frac{1}{\sqrt{3}}(duu+udu+uud)##. Why?
 
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Please give a reference to what you are reading.
 
Thomson's book: Modern particle physics. vide figure 9.17 on page 235, for instance, and page 227 where he applies the ladder operators to get the states of the center of the meson octet. In my case, I want to get all the decuplet states from one using the ladder operators.
 
Well, as I understand it now, people use ##uud## as written above as an abbreviation...
 

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