The spin-flavor wavefunction of Sigma+

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Xico Sim
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Hi, guys.

If I want to write the spin-flavor wavefunction of ##\Sigma_+## starting only from knowing that the quark content of the proton is ##uud##, how can I procced?
I started by applying the ladder operators in order to get the baryon octet vertexes. I am now having problems with:
  1. determining the flavor wavefunction for the center octet states (including ##\Sigma_+##).
  2. determining the spin wavefunction for ##\Sigma_+##. Even if I suppose that the its spin state is ##|1/2,1/2\rangle##, there is more than one way for this to happen when we combine 3 spin 1/2 quarks...
Does anyone know a text where I can find something like this done in a comprehensive and detailed way? Or, alternatively, can you tell me a way to do it?
 
Aren't sigma baryons strange ones? Are you using an SU(3) flavor symmetry?
As for the quarks they would be uus ? If you have more than 1 combination then you write them all, as you did for the proton [when you had the mixed symmetric states].
the flavor states can be obtained in a similar way by combining u,u and s.
 
The problem is that I did not understand the derivation of the proton wavefunction also: I found Griffiths, and for that matter every other text I found on the subject, quite confusing. Do you happen to know a place where it is clearly and thoroughly explained?
 
Using Thomson's book I understood the derivation of the proton spin-flavour wavefunction. I will try to apply what I learned to this case.
 
ChrisVer said:
what is confusing?

To make myself clear, I posted my attempt. I arrived at the correct wavefunction, but I have a problem with it: even though it seems symmetric, I would expect it to be only mixed symmetric (only symmetric in 1,2), since ##X## is only symmetric in 1,2 and ##\phi## is completely symmetric...
 
Attachments
  • Handwritten notes on total wavefunction psi = phi_flavour chi_spin xi_space zeta_colour; colour antisymmetric for baryons, space symmetric for L=0, so phi chi must be antisymmetric; Sigma0 has spin 1/2 and quark content uds, flavour state |I=1, I3=0>.
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  • Handwritten notes deriving the spin-flavor state of three quarks: 1 quark with E = E(1/2), 2 quarks as E(1/2) tensor E(1/2) = E(0) + E(1), and 3 quarks as (E(0) plus E(1)) tensor E(0) = E(0) plus E(1), with |Λ> = |0,0>.
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  • Handwritten notes: Now, φ(1,0) ∈ E(1); φ(1,0) is symmetric (S); φ(1,0) = Ŝ(uds) = (1/√3!)(uds + usd + dus + dsu + sud + sdu); symmetrization operator; DETERMINING χ = χ(S=1/2, m_S=1/2); I choose e.g. m_S=1/2; We combine 3 quarks E(1/2) ⊗ E(1/2) ⊗ E(1/2) = ...
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  • Handwritten derivation on lined paper: E(1/2) tensor E(1/2) tensor E(1/2) = (E(0) plus E(1)) tensor E(1/2) = E(1/2) plus E(1/2) plus E(3/2); since S = 1/2, X not in E(3/2); X = |1/2, Y2> = sqrt(2/3)|1, -1/2> - (1/sqrt3)|0, 1/2>, from the CG coefficients table; states to be written on the basis m1, m2, m3.
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  • Handwritten notes on squared paper deriving spin states of three quarks, with bra-ket expressions for |1, -1/2> and |1, 1>, and a boxed note that s12 is in {0, 1}.
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  • Handwritten derivation of a two-particle spin state |0, 1/2> built from |1/2, 1/2> and |1/2, 1/2> with a Clebsch-Gordan style expansion, giving (up-down-up + down-up-up) over root 2 for a three-spin state.
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  • Handwritten derivation of a spin wavefunction: |1/2, 1/2> = sqrt(2/3) ↑↑↓ - (1/sqrt6)(↑↓↑ + ↓↑↑), then (1/sqrt6){2↑↑↓ - ↑↓↑ - ↓↑↑}, then psi = (1/6)(uds + permutations) times that spin state, ending with psi(Sigma+).
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Why is phi symmetric? aren't you using a uds? I am sorry but I don't see why you wouldn't consider the antisymmetric singlet.
 
ChrisVer said:
I am sorry but I don't see why you wouldn't consider the antisymmetric singlet.

When determining ##X##?
 
when determining Phi...
you should have a symmetric one (in the triplet I=1 combination) : [itex]uds + dus[/itex]
and an antisymmetric one (in the singlet I=0 combination) : [itex]uds - dus[/itex]
they both correspond to I3=0
 
Look at look at PR 172, 1807 for simple spin – flavor wave functions for baryons.
 
clem said:
Look at look at PR 172, 1807 for simple spin – flavor wave functions for baryons.

What is PR?