Odd Number Possibilities with a Die: 50% (2 Rolls)

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SUMMARY

The probability of rolling at least one odd number with a die in two rolls is 75%. This is derived from the total combinations of outcomes, where there is a 25% chance of rolling two odd numbers, 25% for two even numbers, and 50% for one of each. To calculate this, one can subtract the probability of rolling two even numbers (25%) from 100%. When rolling a die three times, the probability of getting at least one odd number increases to 87.5%, calculated as 1 minus the probability of rolling all even numbers (12.5%).

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Hepic
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To bring odd number with a die,is 50%.
If I play with the die two times,how possibilities I have to bring odd number?
 
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There would be a 25% chance of getting two odd numbers, 25% chance of two even numbers and a 50% chance of getting one of each. So the probability of getting at least one odd number would be 75%.
 
Yea,I am talking about bringing at least one time "odds".
How we find the 75%?
 
Well you can write out all 36 combinations and add them up. Or you can think of it as 100% less the probabability of getting both even which is 100% - 50%x50% = 100%-25%=75%
 
So If I undestood good,If I play "3" times,for the same result,I have 83,3333%.

Right?
 
No, apparently you didn't understand at all. The probability of getting all three even is (1/2)^3= 1/8= 0.125 so the probability of "at least one head in three rolls" is 1- 0.125= 0.875.
 

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