Odd Party Conjecture: Can You Prove or Disprove?

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The discussion revolves around a conjecture regarding a group of people with an even number of members, where each individual is connected to others through direct or indirect relationships. The conjecture posits that this group can be divided into subgroups such that each member in a subgroup knows an odd number of people directly within that subgroup. It is noted that if every member already knows an odd number of people, no splitting is necessary. Participants are encouraged to either prove the conjecture or provide a counter-example, with a request for clarification on the conditions of the group. The conversation highlights the importance of understanding the relationships within the group to explore the validity of the conjecture.
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Conjecture: Consider any group with an even number of people where each member is connected to any other through some chain of people. Then the original group can be split into groups where each member knows an odd number of people directly.

Note: If the party is such that each member knows an odd number of people to begin with, then the null splitting (no splitting at all) does the job.

Can anyone prove this (or find a counter-example)? Good luck!
 
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I think there needs to be some clarification--

Reworded:

Given: A group exists with a non-zero, even number of people. Each person in the group directly knows at least one other person within the group. Further, each person "knows" each other person in the group, either directly or indirectly (via people they know directly).

Conjecture:The group can be split into 1 or more subgroups wherein each member of a subgroup knows an odd number of people directly within that subgroup.DaveE
 
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Thanks DaveE for your reply.

Your clear rephrasing is quite helpful.
 
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