Ode45 for solution of 4 d.o.f. problem

[bugatti79]

Hi Folks,

I have made up this code in an attempt to find the response time a 4 dof problem. However, I do not get an oscillatory response as I expect, instead I get a straight line which drops off towards the end. Not sure what is happening..any ideas..?

function f = Simple_Planetary(t,y)
f = zeros(8, 1);
f(1) = y(2);
f(2) = -y(7)+2*y(1);
f(3) = y(4);
f(4) = -y(7)+2*y(3);
f(5) = y(6);
f(6) = -y(7)+2*y(5);
f(7) = y(8);
f(8) = 3*y(7)-y(1)-y(2)-y(3)+10*cos(t);

y0 = [1;1;1;1;1;1;1;1];
[t,y] = ode45('Simple_Planetary', tspan, y0);
subplot (211)
plot (t,y (: , 1));
xlabel ('t');
ylabel ('x1 (t)');
subplot (212)

plot (t,y (: , 3));
xlabel ('t');
ylabel ('x2 (t)');

Regards

 

[jedishrfu]

Two things that may help are enclosing your source code in code tags. This will eliminate the smiley faces.

The second is it seems this is not the whole program as I can't see what span is defined as.

Lastly, what does d.o.f mean?

 

[bugatti79]

Hi, sorry I forgot a line for the span. That is all the code...
4 dof is a 4 degree of freedom system, ie for independent variables that we are solving for

tspan = [0: 0.01: 20];
y0 = [1;1;1;1;1;1;1;1];
[t,y] = ode45('Simple_Planetary', tspan, y0);
subplot (211)
plot (t,y (:, 1));
xlabel ('t');
ylabel ('x1 (t)');
subplot (212)

plot (t,y (:, 3));
xlabel ('t');
ylabel ('x2 (t)');

function f = Simple_Planetary(t,y)
f = zeros(8, 1);
f(1) = y(2);
f(2) = -y(7)+2*y(1);
f(3) = y(4);
f(4) = -y(7)+2*y(3);
f(5) = y(6);
f(6) = -y(7)+2*y(5);
f(7) = y(8);
f(8) = 3*y(7)-y(1)-y(2)-y(3)+10*cos(t);

 

[DrClaude]

Could you write down the system of equations you are solving?

 

[bugatti79]

Hi

Sorry for the delay. It turns out the my K matrix was incorrect from which I derived the system of equations and hence the reason for the large numbers because my matrix was nearly singular etc.