Ok ty (can u checked this one)

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The discussion centers on the integration of the function dx/(x ln(x)^4). The correct approach involves using the substitution u = ln(x), leading to the integral transforming into (1/4)ln(ln(x)) + C. Participants clarify that the expression (du)(x)/(4x u) is unnecessary, as substituting du for dx/x simplifies the process. The final result confirms the integration technique and highlights the importance of proper substitution in calculus.

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ArmiAldi
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let me know is this correct or no?
dx)/(x lnx^4)
(dx)/(x 4lnx)
(dx)/(4x lnx)
u = lnx
du/dx = 1/x
(du)(x) = dx

lnx = u dx = (du)(x)

(du)(x)/(4x u)
du/4u
(1/4)ln(u)


(1/4)ln(lnx)
 
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ArmiAldi said:
let me know is this correct or no?
dx)/(x lnx^4)
You mean the integral of this don't you?

(dx)/(x 4lnx)
(dx)/(4x lnx)
u = lnx
du/dx = 1/x
(du)(x) = dx

lnx = u dx = (du)(x)

(du)(x)/(4x u)
du/4u
(1/4)ln(u)


(1/4)ln(lnx)
Well, (1/4) ln(ln(x))+ C. And you didn't really need to write "(du)(x)/(4x u)". From du/dx= 1/x, du= dx/x and you can go ahead and substitute du for the dx/x you already have in the integral.
 

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