On the hypergeometric distribution

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madhavpr
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While I do understand the story of the hypergeometric distribution, I was wondering if there's anything "geometric" about it, or if there's any connection between the distribution and "geometry". Can anyone throw some light on it?

Thanks,
Madhav
 
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I don't know the history, but I'll speculate that the "geometric" part comes from the use of the adjective "geometric" in "geometric series". I think a "hypergeometric series" is a generalization of the idea of a "geometric series".
 
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Historically "hypergeometric" was first used for the series and differential equations. It was applied to the distribution because the probability generating function for the distribution involves a hypergeometric function. (That was the explanation provided to use many, many, many, years ago in graduate school.)
 
statdad said:
Historically "hypergeometric" was first used for the series and differential equations. It was applied to the distribution because the probability generating function for the distribution involves a hypergeometric function. (That was the explanation provided to use many, many, many, years ago in graduate school.)

That seems like the right explanation. According to wikipedia:

The term "hypergeometric series" was first used by John Wallis in his 1655 book Arithmetica Infinitorum.

But why did Wallis call this series "hypergeometric"?
 
According to the book "The words of mathematics: an etymological dictionary of mathematical terms used in english" by Steven Schwartzman, we have

hypergeometric ( adjective): from Greek -derived hyper- "over, beyond," and geometric (qq. v.) A hypergeometric series is so named because it "goes beyond" the complexity of a simple geometric series.

And finally, here is an explanation of why geometric series were called like this: https://www.math.toronto.edu/mathnet/questionCorner/arithgeom.html

So it is funny to realize that the name for the hypergeometric distribution (which measures the probability of winning in some sot of lottery) comes from trying to find a square with the same area as a rectangle.