One dimensional motion problems.

Click For Summary
The discussion revolves around three one-dimensional motion problems related to a physics final. The first problem involves a plane landing, where the user calculated acceleration as -5.5 m/s² and time as 20 seconds but is unsure about finding the coefficient of friction. In the second problem, the user found the truck's acceleration to be 0.5 m/s² and displacement as 525 meters but is confused about determining the safe distance from traffic. The third problem involves a police car trying to catch robbers, where the user calculated the acceleration as 1.1 m/s² but feels lost overall. Participants suggest using force equations and setting up simultaneous equations for the truck and traffic to solve the problems.
picklepie159
Messages
19
Reaction score
0

Homework Statement


Hi, Physics Forum!
I have three problems. Since I am having a physics final on Tuesday, I am very nervous that I don't get these. These all concern one-dimensional motion.

1.) A plane is landing on the runway. It stops after 1100 meters, with an initial velocity of 110 meters. The mass is 4000 kilograms. Find A, time, and the coefficient of friction.

2.) A truck enters a highway at velocity of 10 m/s. It must accelerate to 25 m/s in 30 secs. Find the displacement and the acceleration. Now imagine that the flow of traffic is coming behind the truck at 20 m/s. How far away must the truck be not to crash into the traffic?

3.) A police car is at rest when a group of robbers pass them at 35 m/s. The officer starts accelerating when the crooks are at 500 m away. He must catch up to them within 30 seconds. What is the acceleration and displacement covered by the cop?

Homework Equations


I can't really type equations, So I basically know all of the one dimensional motion equations.
(I think). I'm sorry if you view this as lazy, but I am pretty tired right now and might pass out on the computer. Sorry.


The Attempt at a Solution


For number 1, I got the acceleration as -5.5 m/s squared. The time is 20 seconds. Now I am not sure about the mu. Net force is 22000 N, But I can't find anything else (ie. Applied force) to get Mu.

2.) I got the acceleration as 0.5 m/s squared. I then used the displacement forumula, to get d= 525 meters. I don't understand what equation I could use to find the distance from the traffic to the truck.

3.) I got the acceleration as 1.1 m/s squared. Besides that, I am totally lost. I know there is a policy that I have to try to solve my questions first, bit this is way beyond me. You don't have to give me the answers- a small nudge or clue towards it would be greatly appreciated.

Thanks for answering!
 
Physics news on Phys.org
hi picklepie159! :smile:
picklepie159 said:
For number 1, I got the acceleration as -5.5 m/s squared. The time is 20 seconds. Now I am not sure about the mu. Net force is 22000 N, But I can't find anything else (ie. Applied force) to get Mu.

that's fine so far! :smile:

now use F = ma and F = µN :wink:
2.) I got the acceleration as 0.5 m/s squared. I then used the displacement forumula, to get d= 525 meters. I don't understand what equation I could use to find the distance from the traffic to the truck.

now you need to write two equations, one for the truck, and one for "the traffic", both to meet at the same place (but different displacements of course, and the same time t)

(same for question 3)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 22 ·
Replies
22
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K