Python One-line Python Code that returns a sequence of integers

[mathmari]

Hey!

I want to write a one-line Python generator or iterator expression that returns the sequence of integers generated by repeatedly adding the ascii values of each letter in the word “Close” to itself. The first 10 integers in this sequence are: 67, 175, 286, 401, 502, 569, 677, 788, 903, 1004. If the code should not be in one line it would be as follows, or not ?

sum = 0 
for letter in list("Close") : 
    sum += ord(letter) 
    print(sum)

So that we write that in oe line the for-loop will be

sum += [ord(letter) for letter in list("Close")]

right? But how do we add at this line the print? :unsure:

 

[I like Serena]

sum = 0
for letter in list("Close") :
    sum += ord(letter)
    print(sum)

Hey mathmari!

Shouldn't the loop be repeated? (Wondering)

So that we write that in oe line the for-loop will be

sum += [ord(letter) for letter in list("Close")]

right? But how do we add at this line the print?

This doesn't parse since we can't add a list to a number.

I googled how to calculate a cumulative sum in python and found numpy.cumsum.
That is, we can do import numpy; numpy.cumsum([1,2,3]).

We can repeat a list by multiplying it with a number. For instance 5 * [ord(letter) for letter in list("Close")].

We can print a resulting list by calling print before it. For instance print [1,2,3].

 

[mathmari]

I googled how to calculate a cumulative sum in python and found numpy.cumsum.
That is, we can do import numpy; numpy.cumsum([1,2,3]).

We can repeat a list by multiplying it with a number. For instance 5 * [ord(letter) for letter in list("Close")].

We can print a resulting list by calling print before it. For instance print [1,2,3].

Ahh ! So we should write print(numpy.cumsum([ord(letter) for letter in list("Close") ])) , right? :unsure:

 

[I like Serena]

Ahh ! So we should write print(numpy.cumsum([ord(letter) for letter in list("Close") ])) , right?

Yep. (Nod)
And if we add a multiplier before the list, we get:

>>> print(numpy.cumsum(3 * [ord(letter) for letter in list("Close")]))
[  67  175  286  401  502  569  677  788  903 1004 1071 1179 1290 1405 1506]

It matches the first 10 integers in the opening post.

 

[mathmari]

Yep. (Nod)
And if we add a multiplier before the list, we get:

>>> print(numpy.cumsum(3 * [ord(letter) for letter in list("Close")]))
[  67  175  286  401  502  569  677  788  903 1004 1071 1179 1290 1405 1506]

It matches the first 10 integers in the opening post.

Ah ok! I got it! Thank you very much! :geek: