Op-amp integrator and differentiator in real-life

  • Thread starter Thread starter Kruum
  • Start date Start date
  • Tags Tags
    Op-amp
Click For Summary
SUMMARY

The discussion focuses on the practical applications of op-amp integrators and differentiators. An inverter configuration op-amp with a resistor in series and a feedback capacitor functions as an integrator, producing a triangle wave output from a square wave input. Conversely, replacing the input resistor with a capacitor and using a feedback resistor results in a differentiator, yielding positive and negative spikes useful for triggering devices. These concepts are essential for applications such as PID controllers and calculating velocity and position from accelerometer data.

PREREQUISITES
  • Understanding of operational amplifiers (op-amps)
  • Knowledge of circuit configurations (inverter and feedback mechanisms)
  • Familiarity with signal waveforms (square, triangle, and ramp waves)
  • Basic principles of PID controllers
NEXT STEPS
  • Research the design and implementation of PID controllers
  • Explore the use of op-amps in signal processing applications
  • Learn about the integration and differentiation of signals in electronic circuits
  • Investigate the role of op-amps in accelerometer data processing
USEFUL FOR

Electronics engineers, hobbyists working with op-amps, and anyone interested in practical applications of signal processing in circuits.

Kruum
Messages
217
Reaction score
0
I've gone through some light theory on op-amps and can understand that fully. What I don't understand are the real-life applications for integrator and differentiator. What does the output signal looks like? Can somebody shed some light on these?
 
Engineering news on Phys.org
If you use an inverter configuration op amp with a resistor R in series with the neg input and a feedback capacitor C from the output to the neg input, it is an integrator. Put a square wave in and get a triangle wave out. If you put occasional pulses V volts high and T sec wide in, the output will be proportional to the input voltage V divided by R times pulse width T divided by capacitance C.

If you replace the input R with a capacitor, and use a feedback resistor instead of a capacitor, you will get positive and negative spikes out (differentiated signal), good for triggering scalers, etc.
 
if you integrate a constant, you get a ramp. and that you could use to deflect an electron in a CRT to draw a horizontal line, and to gradually move that line a little lower vertically each sweep.

maybe about as interesting as vacuum tubes with today's technology, tho.
 
Thanks for the replies guys! I can't wait to be able to put theory into practise. All these sound like gold, espescially the PID controllere sounds something I'm going to need quite a lot.
 
You can also use them to calculate velocity, & position from accelerometer.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
7K
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
6
Views
4K
  • · Replies 50 ·
2
Replies
50
Views
8K
  • · Replies 9 ·
Replies
9
Views
5K