MHB Open and Closed in V .... D&K Proposition 1.2.17 .... ....

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I am reading "Multidimensional Real Analysis I: Differentiation" by J. J. Duistermaat and J. A. C. Kolk ...

I am focused on Chapter 1: Continuity ... ...

I need help with an aspect of the proof of Proposition 1.2.17 ... ...

Duistermaat and Kolk's Proposition 1.2.17 and the preceding definition (regarding open and closed sets in a set V) read as follows:https://www.physicsforums.com/attachments/7733
View attachment 7734In the above proof of (ii) we read the following:

" ... ... If A is closed in V then A = V \ P with P open in V ... ... "

... BUT in Definition 1.2.16 we read ...

" ... ... A is said to be closed in V if V \ A is open in V ... ... "But ... these two statements are not the same? How do we reconcile the two statements ... specifically how does the statement in the theorem follow from the definition ...

Hope someone can help ...

Peter
 
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Peter said:
In the above proof of (ii) we read the following:

" ... ... If A is closed in V then A = V \ P with P open in V ... ... "

... BUT in Definition 1.2.16 we read ...

" ... ... A is said to be closed in V if V \ A is open in V ... ... "But ... these two statements are not the same? How do we reconcile the two statements ... specifically how does the statement in the theorem follow from the definition ...

Assume that $A$ is closed in the sense of the definition. Then $V \setminus A$ is open in $V$ and $A = V \setminus (V \setminus A)$ so you can take $P = V \setminus A$.
 
Krylov said:
Assume that $A$ is closed in the sense of the definition. Then $V \setminus A$ is open in $V$ and $A = V \setminus (V \setminus A)$ so you can take $P = V \setminus A$.
Hmm ... wish I'd seen that ...:( ...

Thanks for the help Krylov ... appreciate it ...

Peter
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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