I Operator acting on ket state n

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The discussion centers on the application of the operator (N+1)^-1/2 acting on the |n> state of a harmonic oscillator, where N is the number operator defined by N|n>=n|n>. Participants explore the implications of this operator, particularly through the lens of a Taylor series expansion to interpret non-polynomial functions of operators. The equation f(âN)|n> = f(n)|n> is referenced to clarify how functions of operators behave on eigenstates. The operator (N+1)^-1/2 is connected to Susskind's work, indicating its relevance in quantum mechanics. Understanding these operator actions is crucial for deeper insights into quantum state manipulations.
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how does the operator (N+1)^-1/2 α act on a |n> state of harmonic osciliator? N is the number operator N|n>=n|n> and α anihilation operator
I tried playing with the number's operator eigenvalues equation but couldn't get anywhere, can s/b help me out?
 
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If $$\hat{N}\left|n\right\rangle =n\left|n\right\rangle $$
then, by the very definition of function of operators, we have that
$$f(\hat{N})\left|n\right\rangle =f(n)\left|n\right\rangle $$
 
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Jean-Mathys du bois said:
Summary:: how does the operator (N+1)^-1/2 α act on a |n> state of harmonic osciliator? N is the number operator N|n>=n|n> and α anihilation operator

I tried playing with the number's operator eigenvalues equation but couldn't get anywhere, can s/b help me out?
To make sense of a non-polynomial function of an operator, you can interpret it as a Taylor series:
$$(1 + N)^{-1/2} = 1 - \frac 1 2 N + \frac 3 8 N^2 \dots $$
 
The operator (N+1)^-1/2 α , i think is called Susskind
 

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