Operator r is a diagonal matrix in position representation

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In the position representation, the operator r is represented as a diagonal matrix, indicating that the matrix elements of the position operator are non-zero only when the position states are identical. This is illustrated by the equation provided, where the matrix element of the position operator is expressed as the product of the position vector and a delta function, which enforces the condition that the off-diagonal elements vanish. The discussion clarifies that this representation is consistent with the properties of quantum mechanics, specifically in the context of position measurements. The diagonal nature of the operator reflects the physical interpretation that position measurements yield definite values. Understanding this concept is crucial for grasping the implications of the position operator in quantum mechanics.
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What does it mean by "In the position representation -- in which r is diagonal" in the paragraph below? How can we show that?

Screen Shot 2016-01-28 at 4.23.08 am.png


Does it mean equation (3) in http://scienceworld.wolfram.com/physics/PositionOperator.html? (where I believe the matrix is in the ##|E_n>## basis)
 
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The matrix element of position operator ##\hat{\mathbf{r}}## in position representation reads as
$$
\langle \mathbf{r'} | \hat{\mathbf{r}} | \mathbf{r''} \rangle= \mathbf{r'} \delta(\mathbf{r'}-\mathbf{r''})
$$
which vanishes for off-diagonal elements.
 
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Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA

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