Operators having Hermitian/Antihermitian part?

1. Nov 13, 2008

afrano

Someone told me that any operator can be decomposed in a Hermitian and Antihermitian part. Is this true? How? By addition?

2. Nov 13, 2008

Fredrik

Staff Emeritus
$$X=\frac{X+X^\dagger}{2}+\frac{X-X^\dagger}{2}$$

3. Nov 13, 2008

afrano

Of course!

thanks Fredrik