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Operators having Hermitian/Antihermitian part?

  1. Nov 13, 2008 #1
    Someone told me that any operator can be decomposed in a Hermitian and Antihermitian part. Is this true? How? By addition?
  2. jcsd
  3. Nov 13, 2008 #2


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  4. Nov 13, 2008 #3
    Of course!

    thanks Fredrik
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