Optics / interference in thin films

In summary, we are given a soap bubble with a refractive index of 1.33 floating in air and a thickness of 115 nm for its wall. Using the equation 2nt=(m+0.5)(lambda), we can find the wavelength of light that is most strongly reflected, assuming m=0. This assumption is made because using any other value for m would result in wavelengths outside the visible spectrum. The longest wavelength that is most strongly reflected is the desired result.
  • #1
johnj7
27
0

Homework Statement


A soap bubble n=1.33 is floating in air. If the thickness of the bubble wall is 115 nm, what is the wavelength of the light that is most strongly reflected


Homework Equations


2nt=(m+0.5)(lambda)


The Attempt at a Solution


most strongly reflected = constructive interference
t=115 nm
lambda = unknown
n = 1.33
assumption m=0
plug and chug to get lambda

so I got the answer, but I was confused on why we make the assumption that m=0, couldn't m technically be any integer number? Do we just automatically assume that m=0 for "most strongly reflected" if a specific desired wavelength is not given?

thank you!
 
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  • #2
Yes, strictly speaking the question should have said, what is the longest wavelength that is most strongly reflected.
However if you use m>0 you will get wavelengths that are outside the visible band.
 
  • #3


As a scientist, it is important to carefully consider the assumptions that we make in our calculations. In this case, the assumption that m=0 is a reasonable one to make because we are looking for the wavelength of light that is most strongly reflected. This means that we are looking for the wavelength that produces the highest intensity of reflected light, which occurs when there is constructive interference. In order for there to be constructive interference, the path difference between the two reflected rays must be an integer multiple of the wavelength. By assuming that m=0, we are essentially saying that there is no additional path difference caused by multiple reflections within the thin film, and therefore the path difference is equal to the thickness of the film (t). If m were to be any non-zero integer, it would result in a larger path difference and therefore a different wavelength for constructive interference. In this case, m=0 is the most logical assumption to make in order to find the wavelength of light that is most strongly reflected.
 

1. What is the principle behind the interference in thin films?

The principle behind interference in thin films is the interaction of light waves as they pass through different materials with varying refractive indices. When a light wave travels from one medium to another, part of the wave reflects off the interface while the other part continues to travel through. The reflected and transmitted waves can overlap and interfere with each other, resulting in either constructive or destructive interference depending on the thickness and refractive indices of the thin film.

2. How does the thickness of a thin film affect interference?

The thickness of a thin film plays a crucial role in interference. When the thickness of the film is equal to a certain fraction of the wavelength of light, the reflected and transmitted waves will be in phase and result in constructive interference. This is known as a "resonant condition." On the other hand, when the thickness of the film is an odd multiple of half the wavelength, the reflected and transmitted waves will be out of phase and result in destructive interference. This is known as an "antiresonant condition."

3. What is the difference between constructive and destructive interference in thin films?

Constructive interference in thin films occurs when the reflected and transmitted waves are in phase, resulting in a bright spot or maximum intensity. This happens when the thickness of the film is equal to a resonant condition. Destructive interference, on the other hand, occurs when the reflected and transmitted waves are out of phase, resulting in a dark spot or minimum intensity. This happens when the thickness of the film is equal to an antiresonant condition.

4. How do the refractive indices of the two materials in a thin film affect interference?

The refractive indices of the two materials in a thin film play a significant role in determining the intensity of the reflected and transmitted waves. The larger the difference in refractive indices between the two materials, the greater the change in phase between the two waves. This results in a more significant difference between constructive and destructive interference, leading to more distinct fringes in the interference pattern.

5. What are some practical applications of interference in thin films?

Interference in thin films has many practical applications, such as in anti-reflective coatings for lenses and windows, thin-film solar cells, and optical filters. It is also used in devices like Fabry-Perot interferometers for precise measurements of wavelengths and in the production of colorful iridescent films used in various industries, including cosmetics and automotive coatings.

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