Orbitals and Nucleus - Quick question

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SUMMARY

The discussion addresses the necessity of probability orbitals for electrons versus the treatment of the nucleus as a point-like object in atomic models. The difference in mass and the strong inter-nucleon forces contribute to the nucleus's small size, making it easier to depict in textbooks without requiring complex orbital calculations. The conversation highlights that while nucleons do have orbitals, their calculations are more challenging due to the unknown inter-nucleon potential energy function. Additionally, it mentions the limitations of the orbital model of the atom, particularly regarding electron correlation.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with atomic structure and electron orbitals
  • Knowledge of nucleon interactions and potential energy functions
  • Basic grasp of fine structure and hyperfine structure in atomic physics
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  • Research the concept of inter-nucleon potential energy functions
  • Study the fine structure and hyperfine structure corrections in detail
  • Explore advanced quantum mechanics topics related to electron correlation
  • Examine the differences between classical and quantum models of atomic structure
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Students and professionals in physics, particularly those focused on quantum mechanics, atomic structure, and nuclear physics. This discussion is beneficial for anyone seeking to deepen their understanding of the differences between electron and nucleon behavior in atomic models.

Elpinetos
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Just a quick question - how come that for electrons we need probability orbitals, but for the nucleus we don't?
Is it because of the difference in mass? Or because of a bigger matter wavelength?
Can we really pinpoint the location of the nucleus or ist it just easier for textbooks to depict it like in the middle?
Or is it simply because of it's size?
 
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The nucleons have some kind of orbitals too, but they are much more difficult to calculate than electronic orbitals because the inter-nucleon potential energy function is not known exactly. Also, the nucleus can usually be treated as a point-like object in electronic structure calculations because of the large difference in length scales. The nucleus is so small because neutrons and protons are much heavier than electrons and because the interaction between them is strong.

Also note that the orbital model of the atom is just an approximation that neglects electron correlation at least partially.
 
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If you're interested in exactly what corrections there are to get a better model of the hydrogen atom (to start with), wikipedia has excellent articles on
fine structure:
http://en.wikipedia.org/wiki/Fine_structure
and hyperfine structure:
http://en.wikipedia.org/wiki/Hyperfine_structure

Fine structure and hyperfine structure are progrssively higher corrections to the energy levels of the hydrogen atom. One term in the fine structure (the Darwin term) accounts for the nucleus being of nonzero size.
 
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