Order of Eigenvectors in Diagonalization

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The order of eigenvectors in diagonalization is not fixed and can vary based on the chosen ordering of eigenvalues. While some examples may prioritize the largest eigenvalue first, others may arrange them in ascending order. The key is to select an order that suits the specific problem at hand. There are multiple valid approaches to diagonalizing a matrix, allowing for flexibility in eigenvalue arrangement. Ultimately, the choice of ordering should align with the requirements of the diagonalization task.
blackrose75
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I essentially know how to find eigenvalues and thus eigenvectors, though when solving a problem about diagonalization I do not know how to order them (as in, I can find all the eigenvectors but do not know which order to place them into find my X that diagonalizes my A)

In the examples of my book it first seems to be the largest value (putting the eigenvector corresponding to the eigenvector 1 first then the one to -4), but when I go to another example it puts them in order of 0, 1, 1 (each being one of the eigenvalues.)

Apologies if I phrased this question confusingly, it's a bit late and my test is in another day or two.

Thanks.
 
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there's not "one way" to diagonalize a matrix, there's several ways, corresponding to different orderings of the eigenvalues. pick an order of the eigenvalues that works for you.
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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