Organ Pipe Resonance - How long is the pipe?

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    Pipe Resonance
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Homework Help Overview

The discussion revolves around determining the length of an open organ pipe given its fundamental frequency of 262 Hz at a temperature of 20.0°C. Participants explore the relationship between frequency, wavelength, and the physical characteristics of the pipe.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the speed of sound and its application to find the wavelength. Questions arise regarding the relationship between the length of the pipe and the wavelength, particularly whether the length corresponds to half or a quarter of the wavelength.

Discussion Status

The conversation is active, with participants questioning the assumptions about the pipe's ends and the nature of nodes and antinodes. Some guidance is provided regarding the characteristics of standing waves in open pipes, but no consensus on the correct interpretation has been reached.

Contextual Notes

There is an assumption that the organ pipe may be open at both ends, which could influence the interpretation of the wavelength and the corresponding length of the pipe.

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Homework Statement


An open organ pipe has a fundamental frequency - corresponding to the first resonant length -of 262 Hz. The room temperature is 20.0°C. What is the length of the pipe. [The answer is 0.66m]

Given: 262 Hz and 20°C


Homework Equations


v = 332 + 0.59t
v = f λ



The Attempt at a Solution


v = 332 + 0.59t
= 332 + 0.59(20°C)
= 343.8 m/s

v = f λ
343.8 m/s = 262 Hz X λ
λ = 1.3122 m

Therefore, the length of the pipe is 1.3 m.

I realize I may be well off. Thanks for your assistance in advance :!)
 
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Hi MystiqThunder! Welcome to PF! :smile:
MystiqThunder said:
λ = 1.3122 m

Therefore, the length of the pipe is 1.3 m.

But why would the length be equal to the wavelength? :confused:
 
tiny-tim said:
Hi MystiqThunder! Welcome to PF! :smile:


But why would the length be equal to the wavelength? :confused:

I have no idea... I just figured that is the only way to get a length.
 
MystiqThunder said:
An open organ pipe has a fundamental frequency - corresponding to the first resonant length -of 262 Hz.

so the pipe has an open end and a closed end …

so where are the nodes or antinodes at this frequency?
 
tiny-tim said:
so the pipe has an open end and a closed end …

so where are the nodes or antinodes at this frequency?

Well I am assuming the node is on the closed end and on the open end there is an antinode.
 
MystiqThunder said:
Well I am assuming the node is on the closed end and on the open end there is an antinode.

yes :smile:

so how long is the wavelength?​
 
tiny-tim said:
yes :smile:

so how long is the wavelength?​

Oh I see... so the whole pipe would be half a wave length. Right?
 
MystiqThunder said:
Oh I see... so the whole pipe would be half a wave length. Right?
Not quite. Think of one whole wavelength of a sine wave, but only paying attention to the magnitude at each point. It starts at 0, increases to a maximum, returns to zero, increases to a maximum again, and finally back to zero. What fraction of that does the magnitude of vibration at different distances along the pipe look like?
 
one node and one antinode isn't half a wavelength :redface:
 
  • #10
tiny-tim said:
one node and one antinode isn't half a wavelength :redface:
Oh wait! It is a quarter of a wavelength!
 
  • #11
MystiqThunder said:
Oh wait! It is a quarter of a wavelength!

yes! :smile:

hmm … sorry … looking at the answer, i think the question must mean the organ pipe is open at both ends​
 

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