Organ Pipe Resonance - How long is the pipe?

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Homework Statement


An open organ pipe has a fundamental frequency - corresponding to the first resonant length -of 262 Hz. The room temperature is 20.0°C. What is the length of the pipe. [The answer is 0.66m]

Given: 262 Hz and 20°C


Homework Equations


v = 332 + 0.59t
v = f λ



The Attempt at a Solution


v = 332 + 0.59t
= 332 + 0.59(20°C)
= 343.8 m/s

v = f λ
343.8 m/s = 262 Hz X λ
λ = 1.3122 m

Therefore, the length of the pipe is 1.3 m.

I realize I may be well off. Thanks for your assistance in advance :!)
 
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tiny-tim said:
Hi MystiqThunder! Welcome to PF! :smile:


But why would the length be equal to the wavelength? :confused:

I have no idea... I just figured that is the only way to get a length.
 
MystiqThunder said:
An open organ pipe has a fundamental frequency - corresponding to the first resonant length -of 262 Hz.

so the pipe has an open end and a closed end …

so where are the nodes or antinodes at this frequency?
 
tiny-tim said:
so the pipe has an open end and a closed end …

so where are the nodes or antinodes at this frequency?

Well I am assuming the node is on the closed end and on the open end there is an antinode.
 
tiny-tim said:
yes :smile:

so how long is the wavelength?​

Oh I see... so the whole pipe would be half a wave length. Right?
 
MystiqThunder said:
Oh I see... so the whole pipe would be half a wave length. Right?
Not quite. Think of one whole wavelength of a sine wave, but only paying attention to the magnitude at each point. It starts at 0, increases to a maximum, returns to zero, increases to a maximum again, and finally back to zero. What fraction of that does the magnitude of vibration at different distances along the pipe look like?
 
tiny-tim said:
one node and one antinode isn't half a wavelength :redface:
Oh wait! It is a quarter of a wavelength!