Organic II - Reaction of Aromatic Compounds

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SUMMARY

The discussion centers on the reaction of aromatic compounds, specifically the role of propylmagnesium bromide as a Grignard reagent in the context of chloroazirine. The participant correctly identifies chlorine as a good leaving group and discusses the stabilization of the ionized azirine through resonance structures. The methyl group on the bottom ring is recognized as an electron-releasing group that influences the reaction pathway, leading to the major product formation while explaining the absence of the "not observed" product. The participant seeks clarity on the choice of propylmagnesium bromide for this reaction.

PREREQUISITES
  • Understanding of Grignard reagents, specifically propylmagnesium bromide.
  • Knowledge of resonance structures and their stability in organic chemistry.
  • Familiarity with leaving groups in nucleophilic substitution reactions.
  • Basic concepts of electron-releasing and electron-withdrawing groups in aromatic compounds.
NEXT STEPS
  • Research the mechanism of Grignard reactions and their applications in organic synthesis.
  • Study the effects of electron-releasing groups on reaction pathways in aromatic chemistry.
  • Explore the concept of resonance stabilization in organic intermediates.
  • Investigate the criteria for selecting appropriate Grignard reagents in various reactions.
USEFUL FOR

Chemistry students, organic chemists, and researchers interested in aromatic compound reactions and Grignard reagent applications.

StefanoFIU
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Homework Statement



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The Attempt at a Solution


I want to recognize the Cl as a good leaving group. After leaving, I get the ionized form of the chloroazirine reactant. Then, I want to draw some resonance structures to move the charge around the ring.
sadasd-1.jpg



I do not understand the role of propylmagnesium bromide (Grignard reagent?) or what to do next. Also I do not see the the reason why the "not observed" is not observed. Am I correct up until this point? I appreciate any help, preferably any tips that could lead me to the answer, thank you!
 
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Now I'm thinking that the methyl on the bottom ring exerts an effect on the entire compound forcing the propyl chain to attach to the bottom carbon of the chloroazirine (demonstrated in the major product).
 
The compound is asymmetrical. The methyl group is an electron-releasing group which stabilizes the intermediate formed, in this case the ionized azirine (formed upon removal of the Cl leaving group). Thus, the 3rd resonance structure is more stable than the first and second structures. Therefore, we should not expect to form the "not observed" product.

If the above is true, then my only problem left is to understand why propylmagnesium bromide was chosen for this reaction.
 

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