Oxidation and reduction question

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    Oxidation Reduction
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Discussion Overview

The discussion revolves around identifying the oxidation and reduction processes in the chemical reaction 2Mg + O2 -> 2MgO. Participants are exploring the oxidation states of magnesium and oxygen, as well as the electron transfer involved in the reaction.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant states that magnesium has an oxidation number of 2+ and oxygen has an oxidation number of 3+, expressing confusion about the oxidation states in magnesium oxide.
  • Another participant corrects the oxidation number of oxygen to -2 and asserts that magnesium is oxidized by oxygen, indicating that MgO is neutral.
  • A later reply mentions that O2 has an oxidation number of 0 and claims that 2Mg has an oxidation number of +4, questioning how magnesium is losing electrons in the reaction.
  • Another participant reiterates that O2 has an oxidation number of 0 and provides a calculation for the oxidation numbers in MgO, but remains uncertain about the electron loss by magnesium.

Areas of Agreement / Disagreement

Participants express differing views on the oxidation states of magnesium and oxygen, and there is no consensus on how the electron transfer occurs in the reaction.

Contextual Notes

There are unresolved assumptions regarding the oxidation states and the calculations presented by participants, which may depend on differing interpretations of oxidation numbers.

markosheehan
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I am trying to work out which is oxidised and reduced in this reaction2mg + o2 ->2mgo

so the mg has a oxidation number of 2+ and the oxygen has a oxidation number of 3+. I am not sure what the oxidation numbers of magnesium and oxygen are in magnesium oxide as it does not work out and it is not possible going off my initial workings. Any help?
 
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markosheehan said:
I am trying to work out which is oxidised and reduced in this reaction2mg + o2 ->2mgo

so the mg has a oxidation number of 2+ and the oxygen has a oxidation number of 3+. I am not sure what the oxidation numbers of magnesium and oxygen are in magnesium oxide as it does not work out and it is not possible going off my initial workings. Any help?

Hi marko,

Oxygen has an oxidation number of -2.
MgO is neutral.
Magnesium is oxidized by the oxidizer Oxygen.
 
I like Serena said:
Hi marko,

Oxygen has an oxidation number of -2.
MgO is neutral.
Magnesium is oxidized by the oxidizer Oxygen.
02 has an O.N of 0
2mg has a O.N of +4
in 2mgo the O.N is 2(2) +2(-2)

so i am not sure how mg is loosing electrons.
 
markosheehan said:
02 has an O.N of 0
2mg has a O.N of +4
in 2mgo the O.N is 2(2) +2(-2)

so i am not sure how mg is loosing electrons.

$2 Mg$ is neutral.
It loses 2x2 electrons to yield $2 Mg^{2+}$.
$O_2$ gains 2x2 electrons.
Together they form $2 Mg^{2+}O^{2-}$.
 

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