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Parallel plate capacitor

  1. Feb 25, 2012 #1
    1. The problem statement, all variables and given/known data
    A 5800-nF parallel plate capacitor is connected to a 14-V battery and charged.
    What is the charge Q on the positive plate of the capacitor?

    2. Relevant equations
    C = Q/V

    3. The attempt at a solution
    This looks like a very simple question. The capacitor is fully charged so 5800 nF = Q/(14 V)
    14 V x 5800 nF = 81200 nC

    The positive plate will have a +Q net charge and -Q net charge will be on the negative plate.
    My answer is incorrect though.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Feb 25, 2012 #2
    Sorry I am doing this from my iPad. My answer is correct it wanted the answer in scientific notation. Thanks anyways
     
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