Parallel RC Circuits: Charging to 0.75V in Seconds

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Homework Help Overview

The discussion revolves around a parallel RC circuit consisting of a 0.1M Ω resistor and a 10 μF capacitor connected to a 1.5 V source. The original poster is trying to determine the time required for the capacitor to charge to 0.75 V.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply Thevenin's theorem and questions whether the voltage across the capacitor remains constant at 1.5 V due to the parallel configuration. Some participants discuss the implications of a negligible time constant in this context.

Discussion Status

Participants are exploring the implications of the circuit's configuration and the time constant. Some suggest that the time to charge the capacitor is effectively zero, while others confirm this interpretation. There is an ongoing examination of the assumptions regarding the circuit's behavior.

Contextual Notes

There is a mention of the source having negligible resistance, which influences the time constant calculation. The original poster expresses confusion about the voltage behavior in the circuit.

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Homework Statement



A parallel combination of 0.1M Ω resistor and a 10 μF capacitor is connected across a 1.5 V source of negligible resistance. The time (in seconds) required for the capacitor to get charged upto 0.75 V is approximately

(A) ∞
(B) ln 2
(C) log 2
(D) Zero

Homework Equations



##V = V_0(1-e^{\frac{-t}{RC}})##

The Attempt at a Solution



So, V0 should be 1.5 V, and C is 10 μF. However, should't the voltage across the capacitor be 1.5 V at all times because it's in parallel with the resistance? Even if I use Thevenin's theorem, I get the resistance across the capacitor as 0 ⇒ time constant is 0. Please help?
 
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If the 1.5 V source has negligible resistance then your Thevenin idea is correct and the circuit's time constant will be correspondingly negligible (effectively zero seconds). So how long will it take to fully charge the capacitor from 0 V to 1.5 V?
 
Zero, so that should be the answer.
 
Yup.
 
Thanks!
 

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