MHB Can Parallelograms Be Constructed in a Convex Hexagon?

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In a convex hexagon $ABCDEF$, if there exists a point $M$ such that $ABCM$ and $DEFM$ are parallelograms, then it can be conclusively proven that there exists another point $N$ such that $BCDN$ and $EFAN$ are also parallelograms. This conclusion relies on the properties of parallelograms and the geometric relationships within the hexagon. The proof utilizes vector addition and the properties of midpoints to establish the existence of point $N$.

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In a convex hexagon $ABCDEF$ exist a point $M$ such that $ABCM$ and $DEFM$ are parallelograms . Prove that exists a point $N$ such that $BCDN$ and $EFAN$ are also parallelograms.
 

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Proof using vectors:

Let $\vec{a},\vec{b},\vec{c},\vec{d},\vec{e},\vec{f},\vec{m}$ be vectors representing the points $A,B.C,D,E,F,M$. Then $\vec{m} = \vec{c} + (\vec{a} - \vec{b})$. Therefore $$\vec{a} + \vec{c} - \vec{b} = \vec{d} + \vec{f} - \vec{e}$$ and so $$\vec{b} + \vec{d} - \vec{c} = \vec{a} + \vec{e} - \vec{f}.$$ Let $N$ be the point given by the vector $$\vec{n} = \vec{b} + \vec{d} - \vec{c}.$$ Then $N$ has the property that $BCDN$ and $EFAN$ are parallelograms.
 

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