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burton95
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parametric equations --> acceleration
An object is moving at constant acceleration in the x-y plane. Its position and velocity at two different times are given by the following equations:
What is the magnitude of the object’s acceleration (in m/s2) as it moves from the first position to the second position? Hint: solve for the acceleration along each axis separately.
r1= (2m)i + (4m)j
r2= (10m)i + (14m)j
v1= (1m/s)i + (8m/s)j
v2= (7m/s)i + (2m/s)j
I decided to calc magnitude of the velocity
[itex]\left\|[/itex]v1[itex]\right\|[/itex] = (82+12)1/2 = 8.06
mag v2 = (72 + 22)1/2 = 7.2801
(Vf)2=(Vi)2 + 2asΔs
for y
(7.2801)2=(8.06)2+2as(10)
as = -.7457725
for x
(7.2801)2=(8.06)2+2as(8)
as = -.59818
√((-.598182)+(-.74577252) = .95755
Homework Statement
An object is moving at constant acceleration in the x-y plane. Its position and velocity at two different times are given by the following equations:
What is the magnitude of the object’s acceleration (in m/s2) as it moves from the first position to the second position? Hint: solve for the acceleration along each axis separately.
Homework Equations
r1= (2m)i + (4m)j
r2= (10m)i + (14m)j
v1= (1m/s)i + (8m/s)j
v2= (7m/s)i + (2m/s)j
The Attempt at a Solution
I decided to calc magnitude of the velocity
[itex]\left\|[/itex]v1[itex]\right\|[/itex] = (82+12)1/2 = 8.06
mag v2 = (72 + 22)1/2 = 7.2801
(Vf)2=(Vi)2 + 2asΔs
for y
(7.2801)2=(8.06)2+2as(10)
as = -.7457725
for x
(7.2801)2=(8.06)2+2as(8)
as = -.59818
√((-.598182)+(-.74577252) = .95755
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