Parity of theta term of Lagrangian

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
5 replies · 2K views
illuminates
Messages
25
Reaction score
0
I have a very simple question. Let's consider the theta term of Lagrangian:
$$L = \theta \frac{g^2}{32 \pi^2} G_{\mu \nu}^a \tilde{G}^{a, \mu \nu}$$
Investigate parity of this term:
$$P(G_{\mu \nu}^a)=+G_{\mu \nu}^a$$
$$P( \tilde{G}^{a, \mu \nu} ) =-G_{\mu \nu}^a$$
It is obvious. But what about ##\theta##? If ##\theta## is simple number then
$$P(\theta)=\theta$$
And in such case we have:
$$P(L)=-L$$
So Lagrangian is P-odd quantity. Is it normal? Is in physics P-odd Lagrangians somewhere else? What about week interaction? Is week interaction conserve parity of Lagrangian?
 
Physics news on Phys.org
it seems the topic is needed to shift in "High Energy, Nuclear, Particle Physics".
 
illuminates said:
it seems the topic is needed to shift in "High Energy, Nuclear, Particle Physics".

Thread has been moved.
 
  • Like
Likes   Reactions: illuminates
The SU(2) of electroweak interactions break parity maximally as it is a V-A type interaction. It does not include interactions with right-handed particles.
 
Orodruin said:
The SU(2) of electroweak interactions break parity maximally as it is a V-A type interaction. It does not include interactions with right-handed particles.
Thank you for replying. Would you say my reasoning above is true?