Partial derivative of the harmonic complex function

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SUMMARY

The discussion centers on the harmonic function of a complex variable defined as ##F(z)=\frac{1}{z}##. It is established that this function can be expressed as ##F(z)=f(z)+g(\bar{z})##, where it satisfies the condition ##\partial_xg=i\partial_yg##. However, an alternative representation of the function as ##F(z)=\frac{\bar{z}}{x^2+y^2}## does not meet this derivative condition. Additionally, it is confirmed that if F is analytic, then ##\frac{\partial F}{\partial\bar{z}}=0##.

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Adel Makram
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For a harmonic function of a complex number ##z##, ##F(z)=\frac{1}{z}##, which can be put as ##F(z)=f(z)+g(\bar{z})##and satisfies ##\partial_xg=i\partial_yg##. But this function can also be put as ##F(z)=\frac{\bar{z}}{x^2+y^2}## which does not satisfy that derivative equation!

Sorry, I should have put this thread in homework section.
 
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Actually, if F is analytic, \frac{\partial F}{\partial\bar{z}}=0.
 

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