Partial Fraction Simplification

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SUMMARY

The discussion centers on simplifying the partial fraction equation \( 18 = (x^2 + 9) + (Bx + C)(x + 3) \). The textbook states that this expression can be rewritten as \( (B + 1)x^2 + (C + 3B)x + (9 + 3C) \). To derive this, one must perform the multiplication of the binomials \( (Bx + C)(x + 3) \) and combine like terms with \( x^2 + 9 \). The correct expansion and combination yield the coefficients for the polynomial on the right side of the equation.

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tmt1
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I have this partial fraction:

$$ 18 = (x^2 + 9) + (Bx + C)(x + 3)$$

which the textbook says is equal to:

$$(B + 1)x^2 + (C + 3B)x + (9 + 3C)$$

But I don't follow this step. How do I derive this?
 
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Okay, we begin with:

$$\left(x^2+9\right)+(Bx+C)(x+3)$$

What to you get when you carry out the indicated multiplication of the two binomial expressions?
 

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