Particle of Mass M Moving in XY-Plane: Potential Energy & Orbit Analysis

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Reshma
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A particle of mass M is free to move in the horizontal plane(xy-planne here). It is subjected to force [itex]\vec F = -k\left(x\hat i + y\hat j\right)[/itex], where 'k' is a positive constant.
There are two questions that have been asked here:
1] Find the potential energy of the particle.

[tex]\vec \nabla \times \vec F = 0[/tex]
The given force is conservative and hence a potential energy function exists.
Let it be U.
[tex]F_x = -\frac{\partial U}{\partial x} = -kx[/tex]

[tex]F_y = -\frac{\partial U}{\partial y} = -ky[/tex]

[tex]U(x,y) = \frac{k}{2}\left(x^2 + y^2) + C[/tex]

2]If the particle never passes through the origin, what is the nature of the orbit of the particle?

I am not sure what the PE function tells about the trajectory of the particle. Explanation needed...
 
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The potential energy can be used to find the Lagrangian, and then Lagrange's equation can be used to find the motion.

Alternatively, [itex]m \ddot{x} = F_x = -kx[/itex] and [itex]m \ddot{y} = F_y = -ky[/tex] can be solved directly.<br /> <br /> These equations should look very familiar.<br /> <br /> Regards,<br /> George[/itex]
 
George Jones said:
The potential energy can be used to find the Lagrangian, and then Lagrange's equation can be used to find the motion.

Alternatively, [itex]m \ddot{x} = F_x = -kx[/itex] and [itex]m \ddot{y} = F_y = -ky[/tex] can be solved directly.<br /> <br /> These equations should look very familiar.<br /> <br /> Regards,<br /> George[/itex]
[itex] <br /> Thank you for replying.<br /> <br /> So this is a 2-dimensional harmonic oscillator. The general solution would be:<br /> [itex]x = A\cos(\omega_0 t - \alpha)[/itex] & [itex]y = B\cos(\omega_0 t - \beta)[/itex]<br /> <br /> So, the resultant path of these two SHMs would be an ellipse, right?[/itex]
 
Reshma said:
So this is a 2-dimensional harmonic oscillator. The general solution would be:
[itex]x = A\cos(\omega_0 t - \alpha)[/itex] & [itex]y = B\cos(\omega_0 t - \beta)[/itex]

So, the resultant path of these two SHMs would be an ellipse, right?

Yes.

Regards,
George