Particle or Wave? Duality Explained

[rahaverhma]

How anything can be a particle or wave at the same time.

 

[rootone]

Quantum scale objects (electrons say), can be one or the other depending on how you measure them.
I think it's best to just call them quantum objects.

 

[Anujkumar]

Yeah but at a particular time object or a Quantum object behave like a particle or wave but not simultaneously both

 

[rootone]

This might help.
https://en.wikipedia.org/wiki/Quantum_field_theory

 

[Arman777]

Feymann has a good view on this.They are acting just like "Quantum Mechanical Way".This a problem which turning physics to english as he claimed.I agree with Feymann

 

[weirdoguy]

How anything can be a particle or wave at the same time.

Wave-particle duality is an outdated concept, so don't bother too much with that.

 

[rahaverhma]

I just want to know that waves we talk about of particles, are they electromagnetic waves ??
,and when someone is talking about wavelike property of macroscopical objects are they talking about our oscillation up and down ie. Our wave function otherwise how can someone think of us as a wave.

 

[Nugatory]

I just want to know that waves we talk about of particles, are they electromagnetic waves ??

No, the wave we're talking about are not electromagnetic waves.

How anything can be a particle or wave at the same time.

It can't. A quantum object is neither a particle nor a wave, although it has some properties that we usually associate with waves and some properties that we usually associate with classical particles.

 

[rahaverhma]

Which waves are these?

 

[rahaverhma]

I think the quantification of an object is done when there are the interactions b/w entities .

https://www.google.co.in/url?sa=t&s...x28jtvfnGP_UlkifA&sig2=85EJvHS_97qBEmXSHnKwHg

In this video ,an electron is projected and an interference pattern is observed it is acting as wave and it might no longer be a quantum object.

 

[rahaverhma]

I mean what type of wave are they actually are?

 

[vanhees71]

As several posters have noted before, there is no wave-particle dualism in "modern quantum mechanics" (the today still valid version of QM has been developed independently in 1925/26 by Heisenberg+Jordan+Born, Dirac, and Schrödinger).

In non-relativistic quantum mechanics one associates a wave function with the "state" of a single particle like an electron, $\psi(t,\vec{x})$. It takes values in $\mathbb{C}$ (for scalar particles, spin $s=0$) or $\mathbb{C}^{2s+1}$ (for particles with spin $s \in \{1/2,1,\ldots \}$). The meaning of the wave function is that
$$P(t,\vec{x})=|\psi(t,\vec{x})|^2$$
is the probability distribution for the position $\vec{x}$ of the particle at time $t$ (Born's Rule).

All the "quantum weirdness" like "wave-particle duality" and similar ideas of "old quantum theory" vanish, as soon as you accept this probabilistic meaning of the wave function (or more generally any kind of quantum state).

 

[Stavros Kiri]

... "probability waves" ...

 

[Karolus]

As I understand, in modern quantum mechanics, the wave-particle duality was "outdated." There is no duality, there are only quantum objects, or better to say: vectors in the Hilbert space of infinite dimensions. What we perceive as a "wave" is only a "name" just to give a name to something, that "in essence" is a mathematical function, like sin and cos.
And what is sin and cos? Trigonometric functions ...

 

[Stavros Kiri]

What we perceive as a "wave" is only a "name" just to give a name to something, that "in essence" is a mathematical function, like sin and cos.
And what is sin and cos? Trigonometric functions ...

Partially true, but I think there is more to it than that, so I also partially disagree, but the full analysis would have to go on a separate thread. Roughly and briefly three points here:
1. Structure of wave as (amplitude function)×f(x-vt, y, z) [f being sin or cos etc. type function, or combination etc.], or F(x-vt, y, z) in general etc., or includes different types of modulation ...
2. Thus not limited only to sin, cos ... , unless perform Fourier alalysis (expansion).
3. Besides waves there is also wave-packets, very useful and common even in QM, and these are not sin, cos only (nothing but ... , sometimes, unless Fourier ...).

Thus it's a big issue.

 

[N88]

As several posters have noted before, there is no wave-particle dualism in "modern quantum mechanics" (the today still valid version of QM has been developed independently in 1925/26 by Heisenberg+Jordan+Born, Dirac, and Schrödinger).

In non-relativistic quantum mechanics one associates a wave function with the "state" of a single particle like an electron, $\psi(t,\vec{x})$. It takes values in $\mathbb{C}$ (for scalar particles, spin $s=0$) or $\mathbb{C}^{2s+1}$ (for particles with spin $s \in \{1/2,1,\ldots \}$). The meaning of the wave function is that
$$P(t,\vec{x})=|\psi(t,\vec{x})|^2$$
is the probability distribution for the position $\vec{x}$ of the particle at time $t$ (Born's Rule).

All the "quantum weirdness" like "wave-particle duality" and similar ideas of "old quantum theory" vanish, as soon as you accept this probabilistic meaning of the wave function (or more generally any kind of quantum state).

Any reason for separating the scalar particles out of the $\mathbb{C}$ formula, please? Is this OK:

In non-relativistic quantum mechanics one associates a wave function with the "state" of a single particle like an electron, $\psi(t,\vec{x})$. It takes values in $\mathbb{C}^{2s+1}$ (for particles with spin $s \in \{0,1/2,1,\ldots \}$?

Thanks.

 

[sunmaggot]

I remember there were three kinds of interpretations of a measurement on a particle.

1. realist position, which implies that the particle was there before measurement. Because you didn't do measurement, you did not know it was there. This implies a loophole in quantum mechanics that there is hidden variable to determine position of the particle. This is what Einstein believed in.

2. orthodox position, the particle is not anywhere, but observation created a form of measurement (forced wavefunction of the particle to collapse into one determinate state) The method of observation deeply affects the form of measurement you get.

3. agnostic position, refuse to answer such question because it is nutty to ask for position of a particle before measurement.

Bell's inequality proved that the statistic of realist position and orthodox position are different. This eliminated agnostic position. And the result is that orthodox position is correct (This is why Einstein was wrong).

Now back to your question. If you measure position of a particle, you get position of a particle, which is a particle. Now if you measure momentum of the particle, which is related to wavelength by de broglie formula, you get wavelength, which is a wave. Because position and momentum do not commute each other, you cannot get both information accurately. When position wavefunction collapse, you get measurement of a particle, but the momentum measurement is lost. Vice versa, this shows that a free particle has position and momentum, which is particle and wave property. Measurement method will change their property, which is different from classical mechanics. In classical mechanics, properties are static, particle is particle, wave is wave.

 

[PeterDonis]

I remember there were three kinds of interpretations of a measurement on a particle

These descriptions seem oversimplified to me. They also seem to assume a collapse interpretation of QM; there are also no collapse interpretations.

 

[sunmaggot]

These descriptions seem oversimplified to me. They also seem to assume a collapse interpretation of QM; there are also no collapse interpretations.

maybe I used wrong words. Three opinions maybe better?

 

[Karolus]

I remember there were three kinds of interpretations of a measurement on a particle.

1. realist position, which implies that the particle was there before measurement. Because you didn't do measurement, you did not know it was there. This implies a loophole in quantum mechanics that there is hidden variable to determine position of the particle. This is what Einstein believed in.

2. orthodox position, the particle is not anywhere, but observation created a form of measurement (forced wavefunction of the particle to collapse into one determinate state) The method of observation deeply affects the form of measurement you get.

3. agnostic position, refuse to answer such question because it is nutty to ask for position of a particle before measurement.

Bell's inequality proved that the statistic of realist position and orthodox position are different. This eliminated agnostic position. And the result is that orthodox position is correct (This is why Einstein was wrong).

Now back to your question. If you measure position of a particle, you get position of a particle, which is a particle. Now if you measure momentum of the particle, which is related to wavelength by de broglie formula, you get wavelength, which is a wave. Because position and momentum do not commute each other, you cannot get both information accurately. When position wavefunction collapse, you get measurement of a particle, but the momentum measurement is lost. Vice versa, this shows that a free particle has position and momentum, which is particle and wave property. Measurement method will change their property, which is different from classical mechanics. In classical mechanics, properties are static, particle is particle, wave is wave.

I agree, then the "wave particle duality", or whatever you want to call it, is not outdated

 

[Stavros Kiri]

maybe I used wrong words. Three opinions maybe better?

But, as PeterDonis implies, there are more ...
[Three are the most basic and common ones]

 

[sunmaggot]

But, as PeterDonis implies, there are more ...
[Three are the most basic and common ones]

these three are from griffith's book, so maybe there are more.

 

[calinvass]

We call photons quantum objects, that can behave like a wave or like a particle. How can an object behave like a wave? An object is supposed to have its own identity. Can it keep its identity when it behaves like a wave?

 

[PeterDonis]

. How can an object behave like a wave? An object is supposed to have its own identity.

You are using an inadequate definition of "object". Or perhaps "object" is simply an inadequate term to use to describe quantum entities like a photon. "Identity" in the sense you are using that concept simply doesn't apply to such entities.

 

[vanhees71]

Any reason for separating the scalar particles out of the $\mathbb{C}$ formula, please? Is this OK:

In non-relativistic quantum mechanics one associates a wave function with the "state" of a single particle like an electron, $\psi(t,\vec{x})$. It takes values in $\mathbb{C}^{2s+1}$ (for particles with spin $s \in \{0,1/2,1,\ldots \}$?

Thanks.

That's of course true.

 

[vanhees71]

We call photons quantum objects, that can behave like a wave or like a particle. How can an object behave like a wave? An object is supposed to have its own identity. Can it keep its identity when it behaves like a wave?

Again: Wave-particle dualism is an outdated concept for nearly 100 years now, and if there is anything that is no particle, then it's a photon. It is not even possible to define a position observable for it!

 

[Stavros Kiri]

Again: Wave-particle dualism is an outdated concept for nearly 100 years now, and if there is anything that is no particle, then it's a photon. It is not even possible to define a position observable for it!

Then that goes into "particles &_fields (or field particles)", which is a different but relevant kind of dualism question ...

Also

... photon. It is not even possible to define a position observable for it!

that's because in the 2nd quantization the wave function becomes a field operator and gets quantized (into states, e.g. photon states) ...

 

[Stavros Kiri]

We call photons quantum objects, that can behave like a wave or like a particle. How can an object behave like a wave? An object is supposed to have its own identity. Can it keep its identity when it behaves like a wave?

Photons are field particles, and fields can be waves (e.g. Electomagnetic field and EM waves). Furthermore, [in QED] photons (or photon states) are the results of the 2nd Quantization (of the EM Lagrangian). [See also previous post, but please maintain separate.]

Added note: other field particles (or gauge bosons) in the Standard Model are the 8 gluons (mediators or quanta of the Strong interaction), the two W particles (W⁺, W^-) and the one Z particle (Z⁰), i.e. the three Electroweek mediators of the Weindberg-Salam theory, [and, of course, the photon, ... makes a total of 12 field particles]. Then of course there is the Higgs boson(s), that give rise to mass.
Beyond the standard model, the graviton, hasn't been discovered yet.
[Field particles (or gauge bosons) are usually massless, unless they acquire mass with the Higgs mechanism (e.g. Spontaneous Symmetry Breaking) ...]

 

[Debaa]

Wave-particle duality is an outdated concept, so don't bother too much with that.

Its not a concept it's a proven theory and it's not outdated we still use it.

 

[vanhees71]

I've not seen a single empirical evidence for wave-particle duality. So how can you say, it's a "proven theory"? Since 1925, fortunately we do not need to use such shaky and self-contradictory concepts anymore!