Particle position x = 6.00 - 7.00t² stopping time and origin crossing

[fahadff]

Homework Statement

The position function x(t) of a particle moving along an x axis is x = 6.00 - 7.00t², with x in meters and t in seconds.

Homework Equations

(a)[/B] At what time and
(b) where does the particle (momentarily) stop? At what
(c) negative time and
(d) positive time does the particle pass through the origin?

The Attempt at a Solution

0= 6.00-7.00x^2
x=0.925

 

[Mark44]

Homework Statement

The position function x(t) of a particle moving along an x axis is x = 6.00 - 7.00t², with x in meters and t in seconds.

Homework Equations

(a)[/B] At what time and
(b) where does the particle (momentarily) stop? At what
(c) negative time and
(d) positive time does the particle pass through the origin?

The Attempt at a Solution

0= 6.00-7.00x^2
x=0.925

You have mixed up your variables. The equation is $x = 6 - 7t^2$, so when the position x is 0, the equation becomes $0 = 6 - 7t^2$. When you solve this equation, you get two values of t. One of them is positive and one is negative. These will be the answers to parts c and d.

For parts a and b, you need to calculate the velocity, v(t), and determine at what time(s) it is zero.

 

[FactChecker]

You should also state clearly, which part of the problem you are trying to solve with each set of equations you present in your work.