Particle sliding on a track (cons. of energy problem)

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SUMMARY

The discussion centers on a particle sliding on a track with a flat central section and curved, frictionless ends. The particle is released from a height of 20 cm (L/2) and travels a distance of 62.5 cm on the flat surface before stopping, due to a coefficient of kinetic friction (µk) of 0.32. The final position of the particle is calculated to be 22.5 cm from the left edge of the flat section after accounting for the track's length of 40 cm. The participant initially miscalculated the stopping point but corrected their understanding with guidance from others in the forum.

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A particle can slide along a track with elevated ends and a flat central part, as shown in Figure 8-53. The flat part has length L = 40 cm. The curved portions of the track are frictionless, but for the flat part the coefficient of kinetic friction is µk = 0.32. The particle is released from rest at point A, which is a height h = L/2. How far from the left edge of the flat does the particle finally stop?

08_60.gif


I set this equation:

mgh = μmgd

d = h/μ

d = 20/.32

d = 62.5 cm

Because the answer > L, I subtracted 40 cm from it and got 22.5 cm as the answer (I'm supposed to give it in cm). But it won't accept my answer. What did I do wrong?
 
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You did all the math right to determine distance - the particle will move 62.5 cm on the flat surface before coming to a stop. Now think about the direction it is traveling and where that is in relation to the left edge of the flat surface.
 
Oh, I see.

Thanks a lot for saving me from losing a point. :)
 

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