Determine the partition coefficient of chlorpromazine in DMSO and n-pentane I'm a physics student and doing a course in biophysics. I would really appreciate it, if you would take some time and provide some hints as to how to design a more concrete plan. Especialy, how do I find out the partition coefficient from system A and B? Solubility of CPZ in DMSO: 71 mg/mL Molecular weight of CPZ: 355,33 g/mol Dissolve 17,7665 mg CPZ in 50 mL DMSO to obtain a 1 mM solution. Prepare a series of samples of pentane with the following volumes (1 ml, 5 ml, 10 ml, 20 ml, 40 ml) and bring 10 ml of the CPZ+DMSO solution into contact with it. Shake the solutions to ensure fast equilibration and then centrifuge to separate the two phases. Use UV-vis to measure the absorbance of chlorpromazine in DMSO and use the absorbance to determine the final concentration of CPZ in pentane. Measure the absorbance between ~200-380 nm. Use LB to determine the concentrations of each solvent to determine. The partition coefficient of system B is defined as the difference in concentration between CPZ in DMSO in system A and the amount of CPZ that has diffused to pentane.