- #1
Pythagorean
Gold Member
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I was curious if there was a non-commutative version of Pascal's triangle for operators (such as those used in brah-ket notation)
The important note is that (a + b)^2 = a^2 + b^2 + ab +ba
where ba != ab
The important note is that (a + b)^2 = a^2 + b^2 + ab +ba
where ba != ab