- #1
Pythagorean
Gold Member
- 4,406
- 316
I was curious if there was a non-commutative version of Pascal's triangle for operators (such as those used in brah-ket notation)
The important note is that (a + b)^2 = a^2 + b^2 + ab +ba
where ba != ab
The important note is that (a + b)^2 = a^2 + b^2 + ab +ba
where ba != ab